Question 1123780
<pre>
Here is another way to look at APPROACH or SEPARATION problems:

RATE OF APPROACH (subtract the rates)
RATE OF SEPARATION (add the rates)

This is an APPROACH problem, so we subtract the rates 

40mph - 32mph = 8 mph

   DISTANCE = RATE&#8729;TIME

{{{matrix(1,3,

(matrix(2,1,DISTANCE,apart)),
""="",
(matrix(3,1,RATE,of,approach))*(matrix(3,1,TIME,to,overtake)) )}}}

{{{matrix(11,3,

1.4, ""="", 8*t,
"","","",
1.4/8, ""="", 8*t/8,
"","","",
matrix(1,2,0.175,hr), ""="",t,
"","","",
((matrix(1,2,0.175,hr) )/1)(( matrix(1,2,60,min) )/matrix(1,2,1,hr)), ""="",t,
"","","",
((matrix(1,2,0.175,cross(hr)) )/1)(( matrix(1,2,60,min) )/matrix(1,2,1,cross(hr))), ""="",t,
"","","",
matrix(1,2,10.5,min),""="",t)}}} 
 
Edwin</pre>