Question 1123784
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<pre>
Let x = the amount invested at 7%.


Then the amount invested at 19% is (3x+35000) dollars.


Your equation is 


    <U>interest</U> + <U>interest</U> = <U>total interest</U>,   or


    0.07x    + 0.19*(3x + 35000) = 34090.


Simplify and solve for x.


    (0.07 + 0.19*3)x = 34090 - 0.19*35000


    x = {{{(34090 - 0.19*35000)/(0.07+0.19*3)}}} = 42875.


<U>Answer</U>.  $42875 was invested at 7%  and  3*42875+35000 = 163625 dollars was invested at 19%.


<U>Check</U>.  0.07*42875 + 0.19*163625 = 34090 dollars.   ! Correct !
</pre>

Solved.


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It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.