Question 1123520
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<pre>
Let the numbers are n, n+1, n+2 and n+3.


Then the condition says 


4*(n + (n+3)) > 6*(n+2)


4n + 4n + 12 > 6n + 12


8n + 12 > 6n + 12


8n - 6n > 12 - 12


2n > 0


n > 0.
</pre>

<U>Answer</U>.  &nbsp;&nbsp;Any four consecutive integers &nbsp;n, &nbsp;n+1, &nbsp;n+2 &nbsp;and &nbsp;n+3 &nbsp;with &nbsp;n > 0 &nbsp;satisfy the problem's condition.



<U>Be aware</U>. &nbsp;&nbsp;The solution by &nbsp;@JessLynnLancaster24 &nbsp;is totally wrong and contains a lot of errors,
demonstrating extremely low level in Math.


This forum is not the place for such solutions and such &nbsp;"tutors".