Question 1123684
let h = the price of one hockey ticket.
let b = the price of one baseball ticket.


your equations are:


2h + b = 110.40
1h + 2b = 106.32


thse are two equations that need to be solved simultaneously because the same value of h and b will apply equally to each equation.


multiply both sides of the first equation by 2 and leave the second equation as is to get:


4h + 2b = 220.80
1h + 2b = 106.32


subtract the equation from the first to get 3h = 114.80


solve for h to get h = 114.80 / 3 = 38.16


replace h with 38.16 in the second equation and solve for b as shown below.


1 * 38.16 + 2b = 106.32
subtract 38.16 from both sides of the equation to get:
2b = 68.16
solve for b to get b = 68.16 / 2 = 34.08


you have h = 38.16 and b = 34.08


that's your solution.


replace h and b in the original equations to confirm the solution is correct.


2h + b = 110.40 becomes 2*38.16 + 34.08 = 110.40 which becomes 110.4 = 110.4, confirming the solution is correct in the first equation.


1h + 2b = 106.32 becomes 1*38.16 + 2*34.08 = 106.32 which becomes 106.32 = 106.32, confirming the solution is correct in the second equation.


your solution is that the price of one hockey ticket is 38.16 and the price of one baseball ticket is 34.08.