Question 1123596
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Let *[tex \Large x] represent the width of the frame.  Since there is a frame around all four sides, there are two of these *[tex \Large x] dimensions added to each of the length and width of the original picture, so the length <i>with</i> the frame is *[tex \Large 8\ +\ 2x], and the width <i>with</i> the frame is *[tex \Large 5\ +\ 2x], and since the total area is 180 inē:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  (8\ +\ 2x)(5\ +\ 2x)\ =\ 180]


Multiply it out, put the equation in standard form, and solve the quadratic for the positive value of *[tex \Large x].  The negative root is discarded because a negative number for a measurement of length is nonsense.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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