Question 1123522
(z + 1)^4 = 16(z - 1)^4
(z + 1)^4 = 2^4*(z - 1)^4
(z + 1)^4 = (2z - 2)^4
z+1 = 2z-2
z = 3
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{{{z^4 + 4z^3 + 6z^2 + 4z + 1 = 16z^4 - 64z^3 + 96z^2 - 64z + 16}}}
{{{15z^4 - 68z^3 + 90z^2 - 68z + 15 = 0}}}
Divide by (z-3)
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{{{15z^3 - 23z^2 + 21z - 5 = 0}}}
By graphical methods (or by Newton's method) z = 1/3
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Divide by (z-1/3)
{{{15z^2 - 18z + 15 = 0}}}
{{{5z^2 - 6z + 5 = 0}}}
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*[invoke solve_quadratic_equation 5,-6,5]
z = (3/5) + 4i/5
z = (3/5) - 4i/5