<PRE><B>Question 101730</B>
The sum of three numbers is 123. The second number is 9 less than two times the first number. The third number is 6 more than three times the first number. Find the three numbers.
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Let the numbers be a,b,c
EQUATION:
a+b+c=123
b = 2a-9
c = 3a+6
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Rearrange the equations:
a +b+c = 123
2a-b+0 = 9
3a+0-c = -6
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solve this system of three equations any way you know how.
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I get a=21, b=33, c=69
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Cheers,
Stan H.</PRE>