Question 1123452
p o q put q into wherever there is a x.  So the x^2 becomes (q's function^2) then add 9.
sqrt(x+8)^2+9=x+8+9=x+17 and when x=8, the function equals 25

q o p put p into q wherever there is a x.  So the sqrt (x+8) becomes sqrt (x^2+9 then +8)
sqrt(x^2+9+8)=sqrt(x^2+17), so when x=8 sqrt (81)=9