Question 1123420
Look at the distances of each of these from each other using the distance formula d=sqrt(chg x^2+chg y^2)
sqrt (289) for the first pair and for the adjacent pairs so sides are equal.
The pairs should have orthogonal or perpendicular slopes
the first pair -15/8
the second pair -8/-15 or 8/15, so they are perpendicular
and the other pairs do likewise.
Therefore, the diagonals are (12, 9) and (5, -14) and because it is a square, they should be sqrt(2)*s in length or sqrt(578)
The distance between those two points is sqrt (49+23^2) or sqrt (578)
Doing (20, -6) and (-3, 1) gives the same sqrt (578) distance.
These points are the vertices of a square.
The sides are equal
The sides are perpendicular
The diagonals are s*sqrt(2) more than the sides.