Question 1123422
If the point (x,3) is equidistant from (3,-2) and (7,4). find x
---------
Find the equation of the line thru the 2 points given.
Find the equation of the perpendicular bisector of that line.
Sub 3 for y in that equation.
=============
Or:
{{{d = sqrt((x-3)^2 + 5^2) = sqrt((x-7)^2 + 1)}}}
{{{(x-3)^2 + 5^2 = (x-7)^2 + 1}}}
{{{x^2 - 6x + 34 = x^2 - 14x + 50}}}
{{{-6x + 34 = -14x + 50}}}
8x = 16
x = 2