Question 1123278
{{{graph(450,450,-10,10,-10,10,y=(1/x)+1,y=x+2)}}} 1/x+1=x+2 1/x+1-x-2=0 1/x-x-1=0 1-x<sup>2</sup>-x=0 -x<sup>2</sup>-x+1=0

{{{-x^2-x+1=0}}}

{{{x=(1+- sqrt(5))/-2}}}