Question 101712
Determine the vertex of the parabla: y=(x+2)^2
Vertex form is y-k = (x-h)^2
The vertex is at (h,k)
Your Problem:
y-0 = (x-(-2))^2
Vertex is at (-2,0)
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What is the axis of symmetry?
Axis of symmetry is a vertical line thru the vertex.
Axis of symmetry equation: x=-2
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Cheers,
Stan H.