Question 1123230
<font face="Times New Roman" size="+2">


The first thing you need is the slope of the given line.  Since your given equation is in Standard, *[tex \LARGE Ax\ +\ By\ =\ C], form, you can calculate the slope using *[tex \LARGE m\ =\ -\frac{A}{B}].  Contrast this with determining the slope when the equation is in slope-intercept form:  *[tex \LARGE y\ =\ mx\ +\ b] where the slope is *[tex \LARGE m].


Once you have the slope calculated, use the Point-Slope form:


*[tex \LARGE \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1)]


Where *[tex \LARGE m] is the calculated slope and *[tex \LARGE \(x_1,\,y_1\)] are the coordinates of the given point.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

</font>