Question 101566
{{{(1/4)x}}} +{{{2/3}}}=x+{{{3/4}}}
{{{(1/4)x}}}- x ={{{(3/4)}}} – {{{(2/3)}}}
{{{(1/4)x}}} - {{{(4/4)x}}} ={{{(3/4)*(3/3)}}} – {{{(2/3) * (4/4)}}}
{{{(3/4)x }}} ={{{(9/12)}}} – {{{(8/12) }}}
{{{(3/4)x  =(1/12)  }}}
{{{x =(1/12) /(3/4) }}}
{{{x= (1*4)/(3*12)}}}
{{{ x = (4/36)}}}  divide both by {{{4}}} and we will have
{{{x = (1/9)}}}