Question 101509
Perpendicular to the graph of 4x-y=12 and passes through (8,2)
The slopes of Perpendicular lines are negative reciprocals;
first lets put the equation in standard form;
4x-y=12
-y=-4x+12
y=4x-12; so the slope of this line is 4;
The slope of the perpendicular line is {{{-1/4}}}
Now that we have the slope we use the point-slope form to find the equation;
{{{y-y1=(-1/4)(x-x1)}}}
{{{y-2=(-1/4)(x-8)}}}
{{{y-2=-(1/4)x+2}}}
{{{y=-(1/4)x+2+2}}}
{{{y=-(1/4)x+4}}}; equation of perpendicular line
:)