Question 1123011
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If the second of three consecutive integers is subtracted from 147 the result is the {{{highlight(sum)}}} of the first and the third. 
What are the integers ?
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        Notice how I edited your post in order for it makes sense.



<pre>
Let n be the middle of the three consecutive integers.


The the three integers are (n-1), n and (n+1).


The sum of the first and the third integers is  (n-1) + (n+1) = 2n.


The condition says


    147 - n = 2n.


It is easy to solve:


    147 = 3n  ====>  n = {{{147/3}}} = 49.


<U>Answer</U>.  The integers are  48, 49 and 50.
</pre>

Solved.