Question 1922
z(5z-1)=3z(z+3)    Well, first you need to clear parenthesis.
5z^2-z=3z^2+9z     Invert to = the formula.
2z^2=10z           Now you invert 10z so it resembles the formula.
2z^2-10z=0         Do QF.
{{{x=(-b+-sqrt(b^2-4*a*c))/(2*a)}}}
{{{x=(10+-sqrt(100))/(4)}}}
AFTER YOU DO THE WORK (THIS THING KEEPS SAYING I DID IT WRONG!) THE ANSWER =:
z=5,0       Let's Check!
5(25-1)=15(8)
120=120
0(0-1)=0(0+3)
0=0