Question 1122797
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If *[tex \Large 2x\ +\ 9\ =\ 9], then since *[tex \Large 4x\ +\ 18\ =\ 2(2x\ +\ 9)\ =\ 2*9\ =\ 18] and *[tex \Large 4x\ +\ 12\ =\ 4x\ +\ 18\ -\ 6],


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ +\ 12\ =\ 18\ -\ 6\ =\ 12]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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