Question 101366
Question:

Three consecutive integers add up to 63.  find the middle integer.

Answer:


Here you have three consecutive number...


So you can take them as,   a, a+1 and a+2


their sum is 63



==>  a +(a+1)+ (a+2) = 63


==> a + a + 1 + a + 2  = 63



==> a + a + a + 1 + 2 = 63


==> 3a + 3 = 63 


Subtract 3 from both sides...



==> 3a + 3 - 3 = 63 - 3



==> 3a = 60


Divide both sides by 3



==> {{{ 3a/3 = 60/3}}}



==> a =  20


So the middle number is = a + 1 = 20 + 1 = 21


Hence the answer.


Alos you can find out the three numbers.

a = 20

a+1 = 21

a + 2 = 22


So 20, 21 and 22 are the three consecutive number. and the middle number is 21



Hope you found the explanation useful.



Regards.


Praseena.