Question 1122686
Let {{{ d }}} = distance covered by faster one
{{{ d - .75 }}} = slower one’s distance
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Faster one’s equation:
{{{ d = 4t }}}
Slower one’s equation:
{{{ d - .75 = 3t }}}
{{{ d = 3t + .75 }}}
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By substitution:
{{{ 4t = 3t + .75 }}}
{{{ t = .75 }}}
In .75 hrs they are .75 mi apart
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Check:
{{{ d = 4*.75 }}}
{{{ d = 3 }}}. mi
and
{{{ d = 3*.75 + .75 }}}
{{{ d = 3 }}} mi
OK