<PRE><B>Question 1122657</B>
Ada takes twice as much time as Alice to complete a work
let a = time required by Alice to complete the work
then
2a = time required by Ada
and
 Hope does it in the same time as Ada and Alice together.
h = a + 2a
h = 3a
 If all three working together can finish the work in 6 days,
let the completed job = 1
{{{6/a}}} + {{{6/(2a)}}} + {{{6/(3a)}}} = 1
multiply equation by 6a, cancel the denominators
6(6) + 3(6) + 2(6) = 6a
36 + 18 + 12 = 6a
66 = 6a
 a = 11 days, Alice alone
2a = 22 days, Ada alone
3a = 33 days Hope alone

 
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