Question 1122589
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The probability that the first ticket was drawn for a customer from Pike is the number of people in the drawing from Pike divided by the total number of people in the drawing, namely 2 plus 5 plus 3, or 10.  If the first ticket IS for a person from Pike, then the probability that the second ticket is also for a person from Pike is the number of people who remain in the drawing and who are from Pike divided by the number of people altogether that remain in the drawing.  Then the overall probability is the product of the two probabilities.  Remember that once the first ticket is drawn the numbers will change because the first ticket is not replaced before the second one is drawn.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}

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