Question 1122541
Find the zeros of the related parabola, if any.  The inequality will be true, outside of the zeros, exclusive.



0=2(x-4)^2-3

2(x-4)^2=3

(x-4)^2=3/2

x-4=0+-sqrt(3/2)

x=4+- sqrt(3/2)


The inequality given, will be have y greater than 0, and tend toward infinity, for {{{x<-sqrt(3/2)}}}, and for {{{x>sqrt(3/2)}}}.