Question 1122493
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p\ =\ p_a\ +\ dgh]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p\ -\ p_a\ =\ dgh]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ g\ =\ \frac{p\,-\,p_a}{dh}]

								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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