Question 1122448
P = 2x + 2y, where y = the length of the rectangle
The area, A = x*y
From the first equation, y = P/2 - x
Thus A = (P/2 - x)x
The area will be maximized if dA/dx = 0
dA/dx = P/2 - 2x = 0
This gives x = P/4
Thus y = P/2 - P/4 = P/4
x = y = P/4, which implies the rectangle must be a square