Question 1122401
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Paul made a trip to the recycling plant and back. The trip there took 4 hours and the trip back took 6 hours. He averaged 25 km/h faster on the trip there than on the return trip. What was paul's average speed on the outbound trip?
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<pre>
               SPEED        TIME      DISTANCE
GOING           r            4           d
RETURN         r-25          6           d
</pre>


Same distance d each way.
{{{4r=6(r-25)}}}
Solve this.