<PRE><B>Question 1122372</B>
let age of sam be equal to x.
let age of alex be equal to y.


age of sam is 10 less than 3 times the age of alex.


formula for that is x = 3 * y - 10


the difference between their ages is 28.


formula for that is x - y = 28


in this last formula, solve for x to get x = y + 28


in the first formula, replace x with y + 28 to get y + 28 = 3 * y - 10


subtract y from both sides of the equation and add 10 to both sides of the equation to get:


28 + 10 = 3 * y - y


combine like terms to get 38 = 2 * y


solve for y to get y = 38 / 2 = 19


since x = 3 * y - 10, then x must be equal to 47.


you have:


age of sam is 47
age of alex is 19


age of sam is 3 * age of alex minus 10.
that becomes 47 = 3 * 19 - 10 which becomes 47 = 47, confirming this part of the solution is correct.


the difference between their ages is 28.
47 - 19 = 28, confirming this part of the solution is correct.


solution looks good.


sam is 47 and alex is 19.








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