Question 1122351
.


Since the post by  @josgarithmetic  contains  ERRORS,  I came to fix them.



<pre>
y = mx + b

y = {{{((6-4)/(k-2-0))x+4}}},    b= 4  is given

y={{{(2/(k-2))x+4}}}



According to the condition, the point  (k,0)  is a point on the line
{{{0=(2/(k-2))*k+4}}}


{{{2k/(k-2)}}} = -4


2k = -4(k-2)


2k = -4k + 8

k = -2k + 4

3k = 4


<U>Answer</U>.  k = {{{4/3}}}.
</pre>