Question 1122298
---------------------------------------------
 (ii) 36x^2 + 36y^2 - 24x - 36y - 23 = o
--------------------------------------------


{{{x^2-2x/3+y^2-y=23/36}}}


{{{x^2-2x/3+(1/3)^2+y^2-y+1/4=23/36+(1/3)^2+1/4}}}


{{{(x-1/3)^2+(y-1/2)^2=23/36+1/9+1/4}}}


CENTER AT  ( 1/3,  1/2 )


and then
{{{23/36+4/36+9/36}}}
{{{(23+13)/36}}}
{{{1}}}


{{{r^2}}} is 1, so radius is also 1.