Question 1122281
<pre>
Let x = amount invested at 8%, in dollars.

Then the amount invested at 7.5% is the rest (6000-x) dollars.



The interest from the 8% amount is 0.08*x  dollars.

The interest from the 7.5%   amount is 0.075*(6000-x)   dollars.



Your equation is


    interest + interest      = total interest,   or

    0.08*x  + 0.075*(6000-x) = 464   dollars.


    x = {{{(464 - 0.075*6000)/(0.08-0.075)}}} = 2800.


<U>Answer</U>.  The amount invested at 8% is $2800;  the rest  $6000-$2800 = $3200 is the amount invested at 7.5%.


<U>Check</U>.   0.08*2800 + 0.075*3200 = 464.   ! Correct !
</pre>

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It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.