Question 1122282
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(1) Twice the length of a rectangle increased by three times the width is 48 feet: 2w+3l = 48<br>
(2) The perimeter is 40 feet: 2w+2l = 40<br>
Either by looking at those equations, or by thinking logically about the given information, the difference between those two measurements is the width of the rectangle.<br>
Finishing the problem from there should be easy.