Question 1122290
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Let the four arithmetic means be a, b, c, and d.  Then the arithmetic sequence formed is<br>
-10, a, b, c, d, 2<br>
In that arithmetic sequence -- as in any arithmetic sequence -- the terms can be grouped in pairs with each pair having the same sum.<br>
{{{a+d = b+c = (-10)+2 = -8.}}}<br>
So the sum of the four arithmetic means is 2(-8) = -16.<br>
In general, the sum of n arithmetic means between a and b is n times the average of a and b.<br>
For this problem in particular, the average of the given two terms is (-10+2)/2 = -4; the sum of the four arithmetic means is 4(-4) = -16.