Question 1122269
The glasses are like cylinders.  


Let radius for smaller glass be 3r.


SMALL:
{{{v=3*pi*(3r)^2}}}
{{{v=27pi*r^2}}}


LARGE:
{{{V=5*pi*(5r)^2}}}
{{{V=125pi*r^2}}}



54 of the larger glass was needed.
x of the smaller glass to be needed.
-
{{{54*125pi*r^2=x*27pi*r^2}}}
Solve for x.