Question 1122263
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Here's the way I think of this kind of problem.  Perhaps (I hope) you will get responses from other tutors showing you the way they work problems like this -- in case my method doesn't "work" for you.<br>
(1) In the numerator I have "6x"; in the denominator I have just "x".  That means the whole number part of my answer is going to be 6.  (and you can see that in the answer choices).<br>
(2) So make a fraction with denominator (x+4) that is equivalent to the whole number 6:<br>
{{{6 = (6(x+4))/(x+4) = (6x+24)/(x+4)}}}<br>
(3) Now, how does the numerator of that fraction compare to the denominator of the given fraction?  I have 6x+24 and I want 6x-1.<br>
{{{(6x+24)-25 = (6x-1)}}}<br>
(4) So {{{(6x-1)/(x+4) = (6(x+4)-25)/(x+4) = 6 + (-25)/(x+4) = 6 - (25/(x+4))}}}<br>
Answer A.