Question 1122017
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Z_{low}\,=\,\frac{56\ -\ 63.4}{2.6}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Z_{high}\,=\,\frac{76\ -\ 63.4}{2.6}]


Calculate your Z-scores.  Look up the Low-end score probability and subtract it from the high-end score.  Do a reality check on your results, you are nearly 3-sigma on the low end and nearly 5-sigma on the high end.  Hence your answer has to be in the very high 90s.  Provided the given mean and standard deviation are accurate, it would be extremely rare to find a woman who would be disqualified because of height.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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