Question 1122057
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<pre>
x + y = 77     (1)
8x = 6y        (2)


From the first equation, express y = 77-x  and substitute it into equation (2)


8x = 6*(77-x),


8x = 6*77 - 6x


8x + 6x = 6*77


14x = 6*77  ====>  x = {{{(6*77)/14}}} = 33.


Then y = 77 - 33 = 44.


<U>Answer</U>.  The larger number is 44.
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Solved.