Question 101356
Consecutive even integers follow the form: {{{2x}}}, {{{2x+2}}}, {{{2x+4}}}, ...., etc.



So the product of four consecutive even integers is:


{{{2x+(2x+2)+(2x+4)+(2x+6)=28}}}





{{{8x+12=28}}} Combine like terms on the left side



{{{8x=28-12}}}Subtract 12 from both sides



{{{8x=16}}} Combine like terms on the right side



{{{x=(16)/(8)}}} Divide both sides by 8 to isolate x




{{{x=2}}} Divide


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Answer:

So our answer is {{{x=2}}} 



That means our first number is....


{{{2(2)=4}}}


So our first number is 4



Our second number is simply 2 more than 4


{{{4+2=6}}}


So our second number is 6




Our third number is simply 2 more than 6


{{{6+2=8}}}


So our third number is 8



Our fourth number is simply 2 more than 8


{{{8+2=10}}}


So our fourth number is 10




So our 4 consecutive even integers are 


4,6,8, and 10 



Check:


{{{4+6+8+10=28}}} Add up every integer. They should add to 28



{{{28=28}}} Since they do, the equation is true. So our answer is verified