Question 1121942
.
<pre>
Let "n" be the middle of the three consecutive odd integer numbers. 


Then the numbers are  (n-2), n and (n+2), and their sum is 

    (n-2) + n + (n+2) = 3n.


Then the condition says that


    3n = 4n - 13.


Simplify and solve it:


    13 = 4n - 3n  ====>  13 = n.


<U>Answer</U>.  The three numbers are  11, 13 and 15.
</pre>

Solved.