Question 101328
Start with the given distance formula

{{{d=sqrt((x[1]-x[2])^2+(y[1]-y[2])^2)}}} where *[Tex \Large \left(x_{1}, y_{1}\right)] is the first point *[Tex \Large \left(-3,0\right)] and *[Tex \Large \left(x_{2}, y_{2}\right)] is the second point *[Tex \Large \left(4,0\right)]


{{{d=sqrt((-3-4)^2+(0-0)^2)}}} Plug in {{{x[1]=-3}}}, {{{x[2]=4}}}, {{{y[1]=0}}}, {{{y[2]=0}}}


{{{d=sqrt((-7)^2+(0)^2)}}} Evaluate {{{-3-4}}} to get -7. Evaluate {{{0-0}}} to get 0. 


{{{d=sqrt(49+0)}}} Square each value


{{{d=sqrt(49)}}} Add


{{{d=7}}} Simplify the square root  (note: If you need help with simplifying the square root, check out this <a href=http://www.algebra.com/algebra/homework/Radicals/simplifying-square-roots.solver> solver</a>)


So the distance between (-3,0) and (4,0) is 7 units