Question 1121850
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I edited your question so that it could be read, and I'm going to go way out on a limb and assume that by "10x7" you actually meant 10x - 7.  (It can't be 10x + 7 because that would make x a negative number and then angle RQT would have a negative measure -- an absurd idea indeed).


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 10x\ -\ 7\ =\ 4x\ +\ 6\ +\ 5x]


Solve for *[tex \Large x], then calculate *[tex \LARGE 10x\ -\ 7].


Next time that you are this lazy and sloppy about your postings, I'll just throw your submission in the trash.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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