Question 1121844
distance=rate*time
D=40*t1
D=70*t2
t2=t1-6
Therefore, 40*t1=70(t1-6)
40t1=70t1-420
420=30t1
t1=14 hours
distance is therefore 40*14=560 km ANSWER

6 hours fewer is 8 hours and 70*8=560 km