Question 1121834
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*[tex \Large \text{Almost.  If } 2\sin(x)\ -\ 1\ =\ 0\ \text{ then } 2\sin(x)\ =\ 1\text{ and } \sin(x)\ =\ \frac{1}{2}\text{, not } -\frac{1}{2}.]


*[tex \Large \text{Hence, }x\ \in\ \{\frac{\pi}{6},\,\frac{\pi}{2},\,\frac{5\pi}{6},\,\frac{3\pi}{2}\}]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
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