Question 1121762
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<pre>
If "a" is the side length of a square, then the square of its diagonal is


   a^2 + a^2 = 2a^2,  according to Pythagoras.


From the other side, the area of such a square is a^2.


So, to calculate the area in your case, you need to square the diagonal and then divide it by 2:


    Area = {{{8^2/2}}} = {{{64/2}}} = 32 square units.


<U>Answer</U>.  The area of the given square is 32 square inches.
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Solved.



<U>Another way to solve it is THIS</U> :


<pre>
The diagonals divide the square in 4 congruent right angled triangles with the legs of the length 4 unit each.


So the area of each such triangle is  {{{(1/2)*4*4}}} = 8 square units.


Then the area of the entire square is 4 times it, i.e. 4*8 = 32 square units - the same answer</U>.
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