Question 1121788
the two angles which form a linear pair are supplementary,  they always add to {{{180}}}° 

let's say one angle is {{{alpha}}} and the other angle is {{{beta}}}

by definition, {{{alpha+beta=180}}}° ........eq.1

if the measure of one angle is {{{26}}}° greater than the measure of the other angle, we have

{{{alpha=beta+26}}}°....eq.2

substitute {{{alpha}}} from eq.2 in eq.1

{{{beta+26+beta=180}}}° ........solve for {{{beta}}}

{{{2beta=(180-26)}}}°

{{{2beta=154}}}°

{{{beta=154/2}}}°

{{{highlight(beta= 77)}}}°

go to eq.2 and calculate {{{alpha}}}


{{{alpha=beta+26}}}°....eq.2

{{{alpha=(77+26)}}}°

{{{highlight(alpha=103)}}}°