Question 1121701
Let {{{ a }}} = number Lisa sent
Let {{{ b }}} = number Boris sent
Let {{{ c }}} = number Pablo sent
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(1) {{{ a + b + c = 113 }}}
(2) {{{ c = a - 5 }}}
(3) {{{ b = 4c }}}
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There are 3 equations and 3 unknowns,
so it’s solvable
(3) {{{ b = 4*( a - 5 ) }}}
And
(1) {{{ a + 4*( a - 5 ) + a - 5 = 113 }}}
(1) {{{ a + 4a - 20 + a - 5 = 113 }}}
(1) {{{ 6a - 25 = 113 }}}
(1) {{{ 6a = 138 }}}
(1) {{{ a = 23 }}}
And
(2) {{{ c = 23 - 5 }}}
(2) {{{ c = 18 }}}
And
(3) {{{ b = 4*18 }}}
(3) {{{ b = 72 }}}
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Check:
(1) {{{ 23 + 72 + 18 = 113 }}}
(1) {{{ 113 = 113 }}}