Question 1121666
{{{(x^2-2x+3)/(x+1) <= 1}}}......add {{{-1}}} to both sides

{{{(x^2-2x+3)/(x+1)-1 <= 1-1}}}

{{{(x^2-2x+3)/(x+1)-1 <= 0}}}....now get a rid of denominator on the left side; multiply both sides by {{{x+1}}}


{{{((x+1)(x^2-2x+3))/(x+1)-1(x+1) <= 0(x+1)}}}


{{{(cross((x+1))(x^2-2x+3))/cross((x+1))-1(x+1) <= 0}}}


{{{(x^2-2x+3)-1(x+1) <= 0)}}}


{{{x^2-2x+3-x-1 <= 0)}}}


{{{x^2-3x+2 <= 0)}}}......factor completely; write {{{-3x}}} as {{{-x-2x}}}


{{{x^2-x-2x+2 <= 0)}}}....group


{{{(x^2-x)-(2x-2) <= 0)}}}....factor


{{{x(x-1)-2(x-1) <= 0)}}}


{{{(x-2)(x-1) <= 0)}}}

solutions:

if {{{(x-2) <= 0)}}} => {{{x <= 2)}}}

if {{{(x-1) <= 0)}}} => {{{x <= 1)}}}