Question 1121657
Obviously undefined at x=2 and at x=-1.
Notice factor of 1 for y, {{{(x+1)/(x+1)}}}.


HOLE for x at -1.


{{{x-2}}} is found only in denominator, so this makes for vertical asymptote of {{{x=2}}}.


{{{x-4}}} is factor found only in numerator so this is a root or zero of y.
Root is {{{x=4}}}.