Question 1121648
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{{{3x^2+3y^2+2x-4y=0}}}
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{{{x^2+y^2+2x/3-4y/3=0}}}


{{{x^2+2x/3+y^2-4y/3=0}}}


Complete the Squares.


{{{x^2+2x/3+(2/6)^2+y^2-4y/3+(4/6)^2=(1/3)^2+(2/3)^2}}}


{{{(x+1/3)^2+(y-2/3)^2=1/9+4/9}}}


{{{highlight((x+1/3)^2+(y-2/3)^2=5/9)}}}
Center at  (-1/3, 2/3)
Radius  {{{sqrt(5)/3}}}