Question 1121635
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Distance equals rate times time, so Allison's trip is modeled by *[tex \Large d_1\ =\ 70t] while Austin's trip is modeled by *[tex \Large d_2\ =\ 54t].  We can use the same *[tex \Large t] in each model because the time of travel is given as the same.


But we know that *[tex \Large d_1\ =\ d_2\ +\ 48], so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d_2\ +\ 48\ =\ 70t]


Which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d_2\ =\ 70t\ -\ 48]


But that means


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 70t\ -\ 48\ =\ 54t]


Solve for *[tex \Large t], then calculate *[tex \Large 70t]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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