Question 1121631
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<pre>
Let x be an amount invested at  8%, in dollars.


Then the amount invested at  6%  was  (25000-x)  dollars.


Your equation is


    <U>interest</U> + <U>interest</U>       = <U>total interest</U>


    0.08*x   + 0.06*(25000-x) = 1780   dollars.


Simplify and solve for x:


    0.08x + 0.06*25000 - 0.06x = 1780


    0.02x = 1780 - 0.06*2500 = 280  ====>  x = {{{28000/0.02}}} = 14000.


<U>Answer</U>.  $14000 was invested at 8%.  The rest  $25000 - $14000 = $11000 was invested at 6%.


<U>Check</U>.   0.08*14000 + 0.06*11000 = 1780 dollars.    ! Correct !
</pre>

Solved.


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It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.